A die is thrown once. What is the probability of getting a number lying between 1 and 5 ?
Answer:
12
- We know that in a single throw of a die we can get 1,2,3,4,5, or 6.
So, the total number of possible outcomes =6. - Let E be an event of getting a number lying between 1 and 5.
The event E will happen when the number on the die is 2,3, or 4.
Thus, the number of favorable outcomes = 3. - We know that the probability of occurrence of an event E, denoted by P(E) is defined as P(E)= Number of favorable outcomes Total number of possible outcomes
- Therefore, P( getting a number lying betweeen 1 and 5)=P(E)=36=12