If ABCABC is right angled at CC, find the value of cos(A+B)cos(A+B).


Answer:

00

Step by Step Explanation:
  1. We know that sum of the angles of a triangle is 180180
    A+B+C=180A+B+C=180
  2. It is given that angle CC is right angle. Replace C=90C=90 in above equation
    A+B+90=180A+B+90=180
    A+B=18090A+B=18090
    A+B=90A+B=90
  3. Now we know the value of A+BA+B, we can find the value of cos(A+B)cos(A+B)
    cos(A+B)=cos(90)cos(A+B)=cos(90)
    cos(A+B)=0cos(A+B)=0

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